2x+[3x-(x+2)]=2

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Solution for 2x+[3x-(x+2)]=2 equation:


Simplifying
2x + [3x + -1(x + 2)] = 2

Reorder the terms:
2x + [3x + -1(2 + x)] = 2
2x + [3x + (2 * -1 + x * -1)] = 2
2x + [3x + (-2 + -1x)] = 2

Reorder the terms:
2x + [-2 + 3x + -1x] = 2

Combine like terms: 3x + -1x = 2x
2x + [-2 + 2x] = 2

Remove brackets around [-2 + 2x]
2x + -2 + 2x = 2

Reorder the terms:
-2 + 2x + 2x = 2

Combine like terms: 2x + 2x = 4x
-2 + 4x = 2

Solving
-2 + 4x = 2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 4x = 2 + 2

Combine like terms: -2 + 2 = 0
0 + 4x = 2 + 2
4x = 2 + 2

Combine like terms: 2 + 2 = 4
4x = 4

Divide each side by '4'.
x = 1

Simplifying
x = 1

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